0.25x^2+6x=-11

Solution for 0.25x^2+6x=-11 equation:

0.25x^2+6x=-11

We move all terms to the left:

0.25x^2+6x-(-11)=0

We add all the numbers together, and all the variables

0.25x^2+6x+11=0

a = 0.25; b = 6; c = +11;
Δ = b2-4ac
Δ = 62-4·0.25·11
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-5}{2*0.25}=\frac{-11}{0.5}
=-22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+5}{2*0.25}=\frac{-1}{0.5}
=-2
$